Problems

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Two circles of radius R touch at point E. On one of them, point B is chosen and on the other point D is chosen. These points have a property of BED=90. Prove that BD=2R.

Two circles of radius R intersect at points D and B. Let F and G be the points of intersection of the middle perpendicular to the segment BD with these circles lying on one side of the line BD. Prove that BD2+FG2=4R2.

Inside the rectangle ABCD, the point E is taken. Prove that there exists a convex quadrilateral with perpendicular diagonals of lengths AB and BC whose sides are equal to AE, BE, CE, DE.