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Prove the following formulae are true: an+1bn+1=(ab)(an+an1b++bn);a2n+1+b2n+1=(a+b)(a2na2n1b+a2n2b2+b2n).

For a given polynomial P(x) we describe a method that allows us to construct a polynomial R(x) that has the same roots as P(x), but all multiplicities of 1. Set Q(x)=(P(x),P(x)) and R(x)=P(x)Q1(x). Prove that

a) all the roots of the polynomial P(x) are the roots of R(x);

b) the polynomial R(x) has no multiple roots.

Let it be known that all the roots of some equation x3+px2+qx+r=0 are positive. What additional condition must be satisfied by its coefficients p,q and r in order for it to be possible to form a triangle from segments whose lengths are equal to these roots?