Problems

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Found: 126

Prove that if x04+a1x03+a2x02+a3x0+a4 and 4x03+3a1x02+2a2x0+a3=0 then x4+a1x3+a2x2+a3x+a4 is divisible by (xx0)2.

Prove the divisibility rule for 3: the number is divisible by 3 if and only if the sum of its digits is divisible by 3.

While studying numbers and its properites, Robinson came across a 3-digit prime number with the last digit being equal to the sum of the first two digits. What was the last digit of that number if among the number did not have any zeros among it’s digits?

When Robinson Crusoe’s friend and assistant named Friday learned about divisibility rules, he was so impressed that he proposed his own rule:

a number is divisible by 27 if the sum of it’s digits is divisible by 27.

Was he right?