Problems

Age
Difficulty
Found: 2586

For a given polynomial P(x) we describe a method that allows us to construct a polynomial R(x) that has the same roots as P(x), but all multiplicities of 1. Set Q(x)=(P(x),P(x)) and R(x)=P(x)Q1(x). Prove that

a) all the roots of the polynomial P(x) are the roots of R(x);

b) the polynomial R(x) has no multiple roots.

Prove that for n>0 the polynomial nxn+1(n+1)xn+1 is divisible by (x1)2.

Let it be known that all the roots of some equation x3+px2+qx+r=0 are positive. What additional condition must be satisfied by its coefficients p,q and r in order for it to be possible to form a triangle from segments whose lengths are equal to these roots?

Let z1 and z2 be fixed points of a complex plane. Give a geometric description of the sets of all points z that satisfy the conditions:

a) argzz1zz2=0;

b) argz1zzz2=0.

Prove that amongst any 7 different numbers it is always possible to choose two of them, x and y, so that the following inequality was true: 0<xy1+xy<13.