For a given polynomial \(P (x)\) we describe a method that allows us to construct a polynomial \(R (x)\) that has the same roots as \(P (x)\), but all multiplicities of 1. Set \(Q (x) = (P(x), P'(x))\) and \(R (x) = P (x) Q^{-1} (x)\). Prove that
a) all the roots of the polynomial \(P (x)\) are the roots of \(R (x)\);
b) the polynomial \(R (x)\) has no multiple roots.
Construct the polynomial \(R (x)\) from the problem 61019 if:
a) \(P (x) = x^6 - 6x^4 - 4x^3 + 9x^2 + 12x + 4\);
b)\(P (x) = x^5 + x^4 - 2x^3 - 2x^2 + x + 1\).
Prove that if the function \(f (x)\) is convex upwards on the line \([a, b]\), then for any distinct points \(x_1, x_2\) in \([a; b]\) and for any positive \(\alpha_{1}, \alpha_{2}\) such that \(\alpha_{1} + \alpha_ {2} = 1\) the following inequality holds: \(f(\alpha_1 x_1 + \alpha_2 x_2 ) > \alpha_1 f (x_1) + \alpha_2 f(x_2)\).